How is voltage divided between two reverse-biased ideal diodes?

Published: 12/01/2019
How is voltage divided between two reverse-biased ideal diodes?
Source: ELECTRONICS.STACKEXCHANGE.COM

Suppose we have two identical ideal diodes (without any resistance or voltage drop). We connect these two diodes in series, in the same direction, and reverse-bias them with voltage V. Now we have two series reverse-biased ideal diodes. There isn't any other element in the circuit. What is the voltage value at the node between the diodes? Maybe one would say V/2 because of the symmetry, but any a

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